Question

Given the length Lis Pm, and height His Im, determine the hydrostatic Force on gate {F}, Location of the center of gravity at the inclined surface(y bar) {y}, location of the center of gravity from the water surface (vertical, h bar) {h}, Location of hydrostatic force from the water surface (inclined) {ycp), and Force {P} necessary to just start opening the ſm-wide gate. Neglect the weight of the gate. Water unit weight 911. N/m Hing 2 m-wide gate H (m) Water 1 Lim

Answer 1

As we know that the action of hydrostatic force in perpendialar to surface at a distance Yep from force surface of water. I'm O F Yee (90-1) P 120 Component of F in horizontal direction, F = F cos (90-0) = F sino Now take a moment about o, Fx oc = Рx AB OC = Ycp-| Pa F' (Ycp-1) F sino (4.356-1) AB 3 460652.36 X 0.8944 ( 3.358) 3 P = 460 899.02 K P = 460.89 KN 3