A 74-g ice cube at 0°C is placed in 841 g of water at 30°C. What is the final temperature of the mixture?
Energy absorbed by ice = mass * Heat of fusion = 74 * 334 = 24,716 Joules
Energy released by water = Mass * Specific heat * delta T = 841 * 4.18 * delta T
841 * 4.18 * delta T = 74 * 334
delta T = 7.02˚
Final temperature of water = 30 - 7.02 = 22.98
The final temperature of the water
74 * 4.186 * (Tf – 0) = 841 * 4.186 * (22.98 – Tf)
74 * Tf = 841 * (22.98 – Tf)
915 * Tf = 19326
Tf = 21.12
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