35)
Given:
Hof(C2H2(g)) = 226.78 KJ/mol
Hof(H2(g)) = 0.0 KJ/mol
Hof(C2H6(g)) = -84.68 KJ/mol
Balanced chemical equation is:
C2H2(g) + 2 H2(g) ---> C2H6(g)
ΔHo rxn = 1*Hof(C2H6(g)) - 1*Hof( C2H2(g)) - 2*Hof(H2(g))
ΔHo rxn = 1*(-84.68) - 1*(226.78) - 2*(0.0)
ΔHo rxn = -311.46 KJ
Option B is closest
Answer: B
help with 35 Use the following table for questions 33-36. Substance Ca(OH)2(s) H&ASO4(aq) Ca(H2ASO4)2(aq) H2O(1) AHt...
#4 4) Given the data in the table below. Δ1Prn for the reaction Ca(OH)2 + 2H3AsO4 → Ca(H2AsO4)2 + 2H2O is kJ. Substance AH't(k/mol) Ca(OF)2 H3As04 Ca(H2As04)2 -23460 H20 986.6 -900.4 -285.9 A)-744.9 B)-4519 C)-4219 D) -130.4 E) -76.4 5) The combustion of titanium with oxygen produces titanium dioxide: Ti (s) +02 (g) → TiO2 (s) When 0.610 g of titanium is combusted in a bomb calorimeter, the temperature of the calorimeter increases from 25.00 °C to 50.50 °C. In...
Given the data in the table below, AH®rxn for the reaction Ca(OH)2 + 2H3A504 - Ca(H2AsO4)2 + 2H20 kl. Substance | AH°F (kJ/mol) Ca(OH)2 -986.6 H3 AsO4 -900.4 Ca(H2AsO4)2 -2346.0 H20 -285.9 0-130.4 0-1048.0 0-79.0 0-476.4 O-76.4 Previous Page Next Page Pag Question 40 (2.5 points) The Lewis electron-dot formula for PH3 has O four bonding pairs of electrons. two bonding pairs and two lone pairs of electrons. three bonding pairs and one lone pair of electrons. one bonding pair...