A typical cell membrane is 8.0 nm thick and has an electrical resistivity of 1.3 ✕...
A typical cell membrane is 8.0 nm thick and has an electrical resistivity of 1.3 ✕ 107 ·m.
If the potential difference between the inner and outer surfaces of a cell membrane is 65 mV, how much current flows through a square area of membrane 1.0µm on a side?
_____A
Homework Answers
The resistance of the membrane is going to be proportional to
the thickness and inversely proportional to the cross-sectional
area: thus
R = 1.3e7 * 8 (nm) / (1 µm)^2
= 1.3e7*8e-9 / (e-6)^2
= 1.3*8 * e10
= 1.04e11
Current I = V/R
= 65 (mV)/(1.04e11)
= 6.5e-2/(1.04e11)
= (6.5/1.04)* e-13
= 6.25e-13 A
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