INSTRUCTIONS: USING THE METHOD OF JOINTS, CALCULATE THE FORCE IN EACH MEMBER OF EVERY
TRUSSES SHOWN. STATE WHETHER EACH MEMBER IS IN TENSION OR COMPRESSION.
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Please answer 1 and 2. : USING THE METHOD OF JOINTS 0R SECTIONS, CALCULATE THE FORCE IN EACH
MEMBER OF EVERY TRUSSES SHOWN. STATE WHETHER EACH MEMBER IS IN TENSION OR COMPRESSION.
Using the method of joints, determine the force in each member of the truss shown. State whether each member is in tension or compression
2. Using the method of joints, determine the force in each member of the truss shown. State whether each member is in tension or compression.
Using the method of joints, determine the force in each member of the truss shown. State whether each member is in tension or compression. Locate the centroid of the plane area shown below:
a) Using the method of joints, calculate the force in each member of the trusses shown. State whether each member is in tension or compression. + L A! Lt BIC! 14m=16m- b) Determine the forces in members AC, AD, and DE. c) Determine the forces in members GI, FH, and GH. -- 5 e 3mm 15 m 60 KN
Problem 1: The truss shown is one of several supporting an advertising panel. Using the method of joints, determine the force in each member of the truss for a wind load equivalent to Do SO0 N 3,75 m the forces shown. State whether each member is in tension or compression. S00 N 3.75 m C 2 m
Problem 1: The truss shown is one of several supporting an advertising panel. Using the method of joints, determine the force in each...
Using the method of joints, determine the force in each member
of the truss shown. State whether each member is in tension or
compression.
-3 m А 1.25 m B 4m 84 kN
1. Using the method of joints, determine the force in each member of the truss shown Figure 1. State whether each member is in tension or compression (25 marks). 5 600 Ib 5 7 5
Using the method of joints, determine the force in each member
of the truss shown. State whether each member is in tension or
compression.
7 kN 24 kN 7 kN B с А 0.8 m DO E F 8 kN -1.5 m- -1.5 m