Consider the line y=-7x+5.
Find the equation of the line that is parallel to this line and passes through the point (3,3).
Find the equation of the line that is perpendicular to this line and passes through the point (3,3).
Note that the ALEKS graphing calculator may be helpful in checking your answer.
Equation of parallel line:
Equation of perpendicular line: 1
SOLUTION :
Given line : y = - 7x + 5
Its slope = - 7
Parallel Line :
Slope of parallel line is = - 7
So, equation of parallel line is : y = - 7x + c
Parallel line passes through point (3, 3) , so, it must satisfy the above
equation of the parallel line:
=> 3 = - 7(3) + c
=> c = 3 + 21 = 24.
Hence, equation of parallel line is : y = - 7x + 24 (ANSWER).
Perpendicular Line :
Slope of perpendicular line is = - 1 / - 7 = 1/7
So, equation of perpendicular line is : y = 1 / 7x + c
Perpendicular line passes through point (3, 3) , so, it must satisfy the above
equation.
=> 3 = 1 / 7 * 3 + c
=> c = 3 - 3 / 7 = 18/7
Hence, equation of perpendicularl line is : y = 1 / 7 x + 18/7 (ANSWER).
SOLUTION :
Given line : y = - 7x + 5
Its slope = - 7
Parallel Line :
Slope of parallel line is = - 7
So, equation of parallel line is : y = - 7x + c
Parallel line passes through point (3, 3) , so, it must satisfy the above
equation of the parallel line:
=> 3 = - 7(3) + c
=> c = 3 + 21 = 24.
Hence, equation of parallel line is : y = - 7x + 24 (ANSWER).
Perpendicular Line :
Slope of parallel line is = - 1 / - 7 = 1/7
So, equation of parallel line is : y = 1 / 7x + c
Parallel line passes through point (3, 3) , so, it must satisfy the above
equation of the parallel line:
=> 3 = 1 / 7 * 3 + c
=> c = 3 - 3 / 7 = 18/7
Hence, equation of parallel line is : y = 1 / 7 x + 18/7 (ANSWER).
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> Under sub-heading perpendicular line : Please replace " parallel line " by " perpendicular line " wherever occurs.
Tulsiram Garg Mon, Oct 18, 2021 2:34 AM