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Constants 1 Periodic Table The figure (Figure 1) shows a solid wire of radius a surrounded by a cylindrical shell with inner

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Answer #1

A)
Consider an Amperian loop with a<r<b. The only current that is enclosed by the Ampereian loop is I, that flows through the inner wire.
Using Ampere's law,
B x 2\pir = \muo I
B = \muoI / 2\pir

B)
Consider an Amperian loop r > b+c
Total current enclosed by the Amperian loop = I - I = 0
Magnetic field = 0

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