Question

1) The Daily Planet has recently moved all their offices to the 79th floor of the Empire State Building, 1) a. which is 294.0 m above the ground. One morning, Perry White and Jimmy Olsen are pouring themselves a cup of coffee when Perry accidently spills some. To avoid getting hit with the hot coffee, Jimmy leaps back, crashing into Lois Lane, who goes crashing through the window. It's c. lucky that just then, Clark Kent enters the newsroom, and witnesses the whole incident. Not wanting to reveal his identity, Clark rushes out of the newsroom, climbs the stairs to the Observation deck on the 100 floor, climbs onto the roof 381.0 m above the ground, and changes into his Superman outfit, all in 2.85 seconds. He dives straight downwards at 6 times the acceleration of gravity to save Lois. The moment he passes Lois on the way down, he starts furiously decelerating landing on hit feet with enough time left to catch Lois as she falls into his arms. Figure 1 - Lois falls out the 75th floor window, 294.0 m above the ground. Exactly 2.85 s later, Superman dives off the roof of the 102t observation deck (381.0 m above the ground) at 6 times the acceleration of gravity. Assuming that both Lols and Superman start from zero velocity and are falling/flying straight down. a) What is the height off the ground at which Superman passes Lois? b) What's the maximum speed reached by Superman? c) If Superman lands on his feet traveling at 27.0 m/s just before hitting the ground, what was his average deceleration once he passed Lois? d) After Superman lands, how much time was left before Lois would have crashed into the round? Page 1 of 1

Answer 1

Given that, Lois is falling from 294m height from ground. Superman is falling down to catch lois from 381 m afliv 9.855 later. u=omls for bolt Superman and Lois. Us = omls.. We zo m/s a = 9 m/s he=294m fall's at t-os as = 69 m/32 hs = 381m. . at t=91855. soy 381-h = Ź 9 (t+2.85, 294-h = 4872 [:- S=ut t{at}] let ń from the ground at where both are at same height 381 - į9 [+ 285)* = 294 - įgth 87 = Ź 9 [+ + 8.1225+507+) - įgt? 87 - (4.9)/8.1225) + (4.8915.7+' t = 1.68 99 ~ 1-695. So, h = 294-4.911-693² = 280m

(6) 294-6 = 1/2 g +² he 280.0051 m (froma'] V-utat V = 9(+) = g.69 (1.693 = 16.562 m/s o Vs = 69261:69) 5.6(16.562) = 99.372 m/s c) de so, lliüm Ve = 27 m/s. Veutat 27= (.877 n tare = 2.7151s. Vs = (2.77512 27. 4.7243 m/s2 2.7751 (d) So, tieft = t total – tcompleted = 2.7751-1068 1:08515