Question

In the CS amplifier shown in the figure above, R_sig = 20 kΩ amplifier input resistance R_in = 80 kΩ, C_gs=2pF, C_gd= 0.5pF, g_m=2mA/V, r_o= 80 kΩ , R_D = 5 kΩ, and R_L = 10 kΩ. (π = 3.14)

a) Determine high frequency cut-off f_{H. (Use Miller Approximation. Use . as the decimal point. Answer in MHz; for 7.89MHz write 7.89 only.)}

VOD RD V RIS R CS V Ro In the CS amplifier shown in the figure above. Rsig = 20 kN amplifier input resistance Rin = 80 kN. Cgs=2pF. Cgd= 0.5pF. &m=2mA/V.1.=80k, Rp = 5 k1, and R1 = 10 k1. (1 = 3.14) a) Determine high frequency cut-off fH (Use Miller Approximation. Use . as the decimal point. Answer in MHz; for 7.89MHz write 7.89 only.)

Answer 1

1 Solution VOD ERD CC 카 V con Reig 3RL 80k RG ² Cs Y TT -Vse Ro=5kn No=80kn R₂ =loke Ge Cgd = o.spf gr= amaly Small signal ac model. Dutput high frequency for at Co- Cds + Cho (ds=o not of given Cro= Cgd (1- A) miller effect for giren Amplifiest Av=-gm (Roll Rello) Rolirullio = 5kl sok Iltok = sk 11 ( 80k 20 pk = 5 kll (8.88 K) = 5kx8.88k 3.2k2 13.88k - gm (3.2k) - (2x10-3)(3-2 x 303) Av= Av = -6.4

- 86.048 X10 H3 Con=0.5pf (1-10) (gd= 0.5pf -0.578 PT Rotho - Rtho= rollRoltre 80k||5k|llok 53.26.2 12 Ho 91T X3.2x10x0.598 X10 HH2 fm = 186.0.48 m H 1 = {84.002] and in -> Abore analysis is ilandard Fer analysis Miller effects wed High frequency at Fapat: further given ci- Cystems fin=80 for all XBOX1o°42.7x1012 Cgs = 2pf C# = Gd (1-Ax), Miller effect 537.685*103 input = 0.537685X10 H3 'fho= 0.537.685 0.5%( 1-1-6.4) = 3-7 Pf in H3

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