Question

The 41-kg uniform triangular plate is supported by two small hinges A and B and the cable system shown. For the horizontal position of the plate, determine all hinge reactions and the tension Tin the cable. Hinge A can resist axial thrust, but hinge B cannot. See Table D/3 in Appendix D for the mass-center location of a triangular plate. POR 0.66 m T 1.10 m 0.17 m 0.34 m 0.34 m 0.17 m c Ay Answers: Z Z Az = Z Z B2= Z T= Z

Answer 1

Given dhat mass eate m= 41 Sltbion Weight bte= (GY981) = 40a.21 N Now dhauairg dhe ree body diogpram pulleyc ue ge- Nbw dhking EF= O ue T 3T-T TC=aT kate e ge:- Now rauirg he ree bod diagpam

0.66 m Bz W 0.17 m By 0.34 m 0.34 m 1.10 m T 2T C 0.17 m X 1.10 x 3

Now whiting he co-dirade o baird s e and D we ge c-Co.5,-0,0)m D (o,0, 0.66) Now wittirgJension T in vedr eom we ge D-C T \D-I Co-o-51uo-1-10)j+(o-66-0K aT) Co-051) o--10) 066-0) TEO139- 1-594j o.956 K) Now taking Emo we ge Co.956T)C)-(40a.21)( = o T 140.241 N Now oking EFa=o we get A E0139D140.241)o - 103.638 N

Now daking Sum a memert alaud aais passirg rom art 8 n y-disrection ue get. - we ger Trus CA68)(wL034)- (E), (0-34)- -(A(o68) (4a. ailo24) - (o456) (140.241) (6-34)-o 134.070 N Now daking Sum momerd obauf oais passing pom kair 2- dinedion Js ue ge): - ue ga ASCO68)+CEC3) = Ao69)(-1594)(140.241) (6-34) =0 111.772 N Noco daking ° we ge O 111.772E.BAu140.241) o - 111.772 N =0 we get Nous taleng B134.070 + (O-56)(140.241) - 402.21o 134.070 N