5)
Potential energy of +15uC due to -10uC ,
V1 = k*Q1*Q2/r
So, V1 = 9*10^9*(+15*10^-6)*(-10*10^-6)/0.04
Similarly Potential energy of +15uC due to +5uC
V2 = 9*10^9*(15*10^-6)*(5*10^-6)/(0.05) <------- distance between +15 uC and +5uC = 5 cm = 0.05 m
Now,
Potential energy of -10uC due to +5uC
V3 = 9*10^9*(-10*10^-6)*(5*10^-6)/(0.03)
Now, these are the only interactions between the charges possible for 3 charges,
So, Vnet = V1 +V2 +V3
So, Vnet = 9*10^9*(15*10^-6)*(-10*10^-6)/0.04 + 9*10^9*(15*10^-6)*(5*10^-6)/(0.05) + 9*10^9*(-10*10^-6)*(5*10^-6)/(0.03)
So, Vnet = -35.25 V
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