An inductor with an inductance of 2.30 H and a resistance of 7.50 ? is connected to the terminals of a battery with an emf of 6.00 V and negligible internal resistance.
(a) Find the initial rate of increase of current in the
circuit.
A/s
(b) Find the rate of increase of current at the instant when the
current is 0.500 A.
A/s
(c) Find the current 0.250 s after the circuit is closed.
A
(d) Find the final steady-state current.
A
given
L=2.3 H
R=7.5 ohm
emf E=6 v
a)
by using kirchhoff law
E-L(di/dt)-iR=0
di/dt=(E-iR)/L
initially i=0
di/dt=E/L
=6/2.3
=2.608 A/sec
b)
di/dt=(E-iR)/L
di/dt=(6-0.5*7.5)/2.3
=0.978 A/sec
c)
i=io[1-e^-(R/L)*t]
=E/R[1-e^-(R/L)*t]
=6/2.3[1-e^-(7.5/2.3)*0.25]
=1.45 A
d)
imax=E/R
=6/2.3
=2.608 A
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