Solve the initial-value problem d2ydt2+10dydt+25y=0,y(1)=0,y′(1)=1. Answer: y(t)=

Question

Question

Solve the initial-value problem $\frac{d^{2} y}{d t^{2}} + 10 \frac{d y}{d t} + 25 y = 0, y (1) = 0, y^{'} (1) = 1.$

Answer: $y (t) =$

Answer 1

Answer #1

answered by: Gevorg

Answer 2

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