Question

roblem 4. (25 pts)A circuit with four inputs, (A, B, C, D), and four outputs (F, G, H, I) is described by the table below. For this circuit Para este circuito a. (10 pts) Express G as a sum of minterms b. (10 pts) Express F as a product of maxterms c. (5 pts) Realize G using just NAND's, and F using only NOR's. BCD/IF G H I 0 1 0 1 1 0 0 1 1 1 1 01 1 1 0

Answer 1

To express 'G' as sum of min terms rightarrow 'k' map for this is 'G' should be expressed as sum of min terms rightarrow G = m (7, 14, 15) rightarrow G = BCD + CAB [From k - map] rightarrow G = ABC + BCD To express 'F' as product of max terms rightarrow 'k' map for this is F = pi M (0, 3, 4, 7, 11) rightarrow F = (A + C + D) (A + C^- + D^-) (B + C^- + D^-) rightarrow F = (A + C + D) (A + C^- + D^-) (B + C^- + D^-) \r\n G = ABC + BCD ABC + BCD = G^= G [Applying complement two times gives same] [G^] = G rightarrow G = ABC BCD Thus 'G' can be realized by using only NAND gates is as follows. F = (A + C + D) (A + C^- + D^-) (B + C^- + D^-) (A + C + D) (A + C^- + D^-) (B + C^- + D^-)