Homework Answers
Energy , E = mc2 =( 1.67 * 10-27) ( 3*108) 2
= 1.50 * 10-10 joules.
this is the rest energy of protons.
SOLUTION :
Rest mass of proton, m = 1.67*10^(-27) kg
Speed of light , c = 3*10^8 m/s
So, rest energy of proton
= m c^2
= rest mass of proton * (speed of light)^2
= 1.67*10^(-27) * (3*10^8)^2
= 1.503*10^(-10) J (ANSWER)
Note :
We can convert it into MeV also, as under :
= 1.503*10^(-10) / (1.602*10^(-19)) eV . [ since 1 eV = 1.602*10^(-19) J ]
= 938.2 * 10^6 eV
= 938.2 MeV
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