Question

1.-) As shown in Figure 1, ABCDO piece is bent from the cylindrical material of 30mm diameter and embedded in the YZ vertical plane and force A = 250N and F2 = 350 N and F3 = 450N are applied to the A end. AB = 100mm, BC = 200mm and CO = 300mm. Find the most critical point on the element and show the stresses that affect this point. Find the safety factor according to the maximum shear stress theory of the element. Sy = 400MPa, Sut = 550MPa, and E = 210 GPa. Y F3 B С F2 A F1 0 X N Şekil 1

Answer 1

O Biver : Fl=250 N ; F2= 350N ; F2 = 450N. Sy = 400 mpa i Sufia 550 mpa, Ez 210 apa dicimeter: 3onem. Solution :. First finding the most critical element and that is at point 63 200 F Lood Fi TI= FlX0.2m 300 mm e T2= F280. Im. Fi 72 Mc Fox0,2m. zo :.Net torque on A = TXT2= FIXO. 2m + T.280.1m = 250*0.2 + 350 40'| 4.- 50+ 35= ESNm (2) MZ = Make 450 x0.2= gorm (2) My = fix 0.3m - 280x03 me 75Nm () (2x0.3m 350*0:3 = 105 NMG) Mormal of force fy = f32 450N fra 250N 'F3 = 450N. shear force of fa-

According to Moxm shear stress theory 021 royt 2XF.S. Tmax = 2 (2) Torsional shear Stres. (TH= 16* T tixd (Tt) 16x 85x10² 16.023 Mipa 1 X 303 450 FY. A = 0.6366 mpa T ūX302 MX 15x10² IT 730% 5-6588 Mpa) I 32 (td) direct shear stress - 350 T 0.4981 Mpa (2) x 20 I Total 16.033+ 0.4951 - 16.528 Mpa 02: 5.6588 i Oy - 0.6366 pmpat) ry 1.4 o H rox. 03x CT Principal stress, on: zchléce) - 34*3:6960) = 1658x10.6%) (6529)?] ry 늘 0 19.865 mpa - 13.5699 Mpa 02

© 19.865-(-13.5699 k 2 400 2x4.0-5) . Fois 11.96 2 12