Answer is (7-2s) /((s-2) (s+1))
And in the given options none of the above
because we clearly observe that in 4th option inplace of (s+1) they gave (s-1)
Check clearly once options
Given the initial value problem below, what is L{f}or Y? Write L{f}or Y. y - y...
Consider the initial value problem for function y, y" – ' - 20 y=0, y(0) = 2, 7(0) = -4. a. (4/10) Find the Laplace Transform of the solution, Y(8) = L[y(t)]. Y(8) = M b. (6/10) Find the function y solution of the initial value problem above, g(t) = M Consider the initial value problem for function y, Y" – 8y' + 25 y=0, y(0) = 5, y(0) 3. a. (4/10) Find the Laplace Transform of the solution. Y(s)...
Consider the initial value problem for function y given by, Consider the initial value problem for function y given by, (a) Find the Laplace Transform of the source function, F(s) = L[-3 F(s) = (b) Find the Laplace Transform of the solution, Y(s) Lt) Y(s) - (c) Find the solution y(t) of the initial value problem above. s(t) Recall: If needed, the step function at c is denoted as u(t - c) -1] Help Entering Answers Preview My Anawers Submit...
(5 points) Consider the following initial value problem: Y" - 2y - 35y = sin(4t) y(0) = 3, y'(0) = -4 Using Y for the Laplace transform of y(t), i.e., Y = L{y(t)}, find the equation you get by taking the Laplace transform of the differential equation and solve for Y(S) = (35+2)/(s^2-25-35)+4/((s^2-28-35)*(s^2+16))
Find the Laplace transform Y(s) = L{y} of the solution of the given initial value problem: 1, y' + 9 = 0<t<T 0,7 <t< y(0) = 5, y'(0) = 4
Solve the initial value problem y" + 3y' + 2y = 8(t – 3), y(0) = 2, y'(0) = -2. Answer: y = u3(t) e-(-3) - u3(t)e-2(1-3) + 2e-, y(t) ={ 2e-, t<3, -e-24+6 +2e-l, t>3. 5. [18pt] b) Solve the initial value problem y' (t) = cost + Laplace transforms. +5° 867). cos (t – 7)ds, y(0) – 1 by means of Answer:
Question 7 3 pts The solution of the Initial-Value Problem (IVP) zy! - 2y = 4(x - 2) y(1) = 4 y (1) = -1 is 1 23 +22 -3 +3 +2.3 -2.0.4 1 Y L 22 - 2.0 + 4 2 None of them 0 4 2.- - 2 + 1 y = 2 Question 8 3 pts The power series solution of the Initial-Value Problem (IVP) (22 +1)yll + xy + 2xy = 0 y(0) = 2 is...
Solve the given initial value problem using the method of Laplace transforms. y'' + 3y' +2y = tu(t-3); y(0) = 0, y'(0) = 1 Click here to view the table of Laplace transforms. Click here to view the table of properties of Laplace transforms. Solve the given initial value problem. y(t) = | Properties of Laplace Transforms L{f+g} = £{f} + L{g} L{cf} = CL{f} for any constant £{e atf(t)} (s) = L{f}(s-a) L{f'}(s) = sL{f}(s) – f(0) L{f''}(s) =...
Solve for Y(s), the Laplace transform of the solution y(t) to the initial value problem below. y" +2y = 2+2 -7,y(0) = 0, y'(0) = - 3 Click here to view the table of Laplace transforms. Click here to view the table of properties of Laplace transforms. Y(s)-
Consider the initial value problem Let L[y(t)] = Y(3), then Y(s) equals Select one: 2s +2 a. O b. 3s +1 s(232 + s +3) 2s2 + s +1 OC s(2s2 + 8 +3) O d. 2s +1-2/3 252 +8 e. 28 +1 -4/5 28² +8
Find the Laplace transform Y (8) = L {y} of the solution of the given initial value problem. y" + 16y S 1, 0 <t<T , YO) = 5, y' (0) = 9 0, <t<oo Enclose numerators and denominators in parentheses. For example, (a - b)/(1+n). Y (8) = Qe