Question

Problem 2 180 mm 120 mm 0 ΑΙ B D С E F F = 277 N h = 155 mm Knowing that the pulley has a radius of 45 mm, Determine the components of the reactions at B and E in N. (The answers may be positive or negative in reference to the given coordinate system) Bx= Answer: By= 1.00 Answer: tion

Answer 1

180 mm 120 mm A B D С h E F F = 277 N h 155 mm

B_x = -616.55 N

B_y = - 184.668 N

E_x = 616.55 N

E_y = 461.668 N
Gin F = 277N, h = 155 mm Pulley radius, 45mm Solution Free body diagram 7: 45 mm B Bx h=155mm FE&77 N E 180 + 120t7 ISO + 120 745 = 345 mm Fig. 1 about Moment direction is 7) E ME (Anticlock wire taken as Positive =0 - 277 x 345 Bxx 155 277 x 345 BxX155 277 x 345 ( 27 Bx 1515 Bx = -616.55 N I E Fx = 0 (algebraic eum of horizontal forces under equilibrium condition) ( left to right direction is taken as positive) Bx & Ex -0 Ex = - Bx =-(-616.55) = 616.55 N

Free body diagram : Member ACE A. &T=277N 7-45mm Cx h = 155mm Cy E 180 mm Ô E Mc =0 C Mornent Fig. 2 about c) x 45 + Ex x 155 - Ey x 180 277 x 45 † 616.55 X 155 Fly x 180 -277 *45 + 616.55 X155 Ey x180 Ey = 83,100.25 - 461.668 N From Fig! Efy (algebraic Sum of vertical forces =o) (upward forces are taken an poartire) +7 Efy=0 - F - Ey Ey + By - F = 0 By = 877-461.668 By = -184.668 N.

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