A student planned an experiment that would use 0.10 M propionic acid, HC3H5O2. Calculate the value...
A student planned an experiment that would use 0.10 M propionic acid, HC3H5O2. Calculate the value of [H+] and the pH for this solution. For propionic acid, Ka = 1.3
Homework Answers
HC3H5O2 <--> H+ and C3H5O2-
Ka = [H+][A-] /[HA]
Ka = 1.3*10^-5
[H+] =[A-] = x
[HA] = 0.1
1.3*10^-5 = x*x /(0.1)
1.3*10^-6 = X^2
x = sqrt(1.3*10^-6 ) = 0.00114
[H+] = 0.00114 M
pH = -log(H+) = -log(0.00114) = 2.94
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A student planned an experiment that would use 0.10 M propionic
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Calculate the pH of a ×1.810−4M aqueous solution of propionic acid.
Round your answer to 2 decimal places.
The acid dissociation K, of propionic acid (C2H3COH) is 1.3 x 10–. Calculate the pH of a 1.8 x 10 *Maqueous solution of propionic acid. Round your answer to 2 decimal places. xs ?
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