Question

Weighing Results for Part A Trial 1 Trial 2 Trial 3 In al 4 Mass of conical flask + KHp/g 93.228 g Mass of conical flask/g Ma

Find:

Moles of NaOH (mol)

Volume of NaOH (L)

Molarity of NaOH mol/L

Average Molarity

Deviation from mean

Average deviation

Percent Relative Average Deviation

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Trial 1: Mars of kHp = 0.4439 L Molar mass of klp = 204.2g/mol. oru Mass 0.4439 -0.00217_ Molar mars - 204.2g/mol moles. I MoDeviation of Trial 1 : 0.0999 -0.0975= 0.0024. Deviation of Trial 2:0.8975 -0.0871 = 0.0104 Deviation of Trial 3: -0.1056 -0.

Add a comment
Know the answer?
Add Answer to:
Find: Moles of NaOH (mol) Volume of NaOH (L) Molarity of NaOH mol/L Average Molarity Deviation...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Please help me find the molarity of NaOH, the average molarity and Standard deviation please. I...

    Please help me find the molarity of NaOH, the average molarity and Standard deviation please. I will give a thumbs up. REPORT SHEET : EXPERIMENT Determination of the 8 Dissociation Constant of a Weak Acid B. Standardization of Sodium Hydroxide (NaOH) Solution Trial 1 Trial 2 Trial 3 Mass of bottle+KHP Mass of bottle Mass of KHP used 0.218 Final buret reading 13.9133 ha Initial buret reading mL of NaOH used Molarity of NaOH Average molarity (show calculations and standard...

  • moles of oxalix acid moles/molarity of NaOH average molarity volume/molarity of hcl used average molarity NAME...

    moles of oxalix acid moles/molarity of NaOH average molarity volume/molarity of hcl used average molarity NAME SECTION DATA SHEET LOCKER A CTOR Write a balanced equation for the reaction between H.CO. and NaOH: 90.33/mol 0.878 0836 TRIAL NUMBER a. Mass of oxalic acid used (g) b. Final Buret reading (ml.] c. Initial Buret reading (ml] d. Volume of NaOH used (b-c) Moles of oxalic acid used f. Moles of NaOH used (2 xe) g. Molarity of NaOH (f/d/1000) Average Molarity...

  • Exact molarity of 1M NaOH used is 1.083M, the volume of NaOH used is 10.0mL, the...

    Exact molarity of 1M NaOH used is 1.083M, the volume of NaOH used is 10.0mL, the final volume of stock NaOH is 100.00mL, and the molarity of stock NaOH solution is 0.1083M. KHP had a molar mass of 204.2 g/mole. acid base titration, part A B. Titration of KHP 1. 2. 3. Mass of KHP Initial buret reading Final buret reading Trial 1 Trial 2 0.30T usly & 0.00ml D.DD_ml 15.3 L 142 ml t is 1/0 ml _mol mol...

  • not sure if molarity of NaOH was calculated correctly and also unsure of how to find...

    not sure if molarity of NaOH was calculated correctly and also unsure of how to find deviation Molarity of KHP: _0.500 Volume of KHP: 25mL How many moles of KHP are in the flask? 1L 0.500 moles - 0.0125 moles KHP 25mL KHP- How many grams of KHP is in the flask? (MW - 204.22g/mol) 0.0125 moles XHP.med = 2.55g KHP Desired NaOH Concentration: Trial #1 2.75 0 Trial #2 2.75 0 Trial #3 2.75 0 33.05 33.01 32.97 Initial...

  • Mass of empty flask (9) Mass of flask + KHP (9) Mass of KHP (g) TRIAL 1 L TRIAL 2 TRIAL 3 94.560g 89.0050 89 7357 9...

    Mass of empty flask (9) Mass of flask + KHP (9) Mass of KHP (g) TRIAL 1 L TRIAL 2 TRIAL 3 94.560g 89.0050 89 7357 94.9109 89.353 : 90.0949 0.250 0.3489 0.3499 0.00171 mol 0.00170.10 0.00171 wol 10.60 mL 0.83 L 60.50mL 10.83 mL 60.50 ML 124-80 with Moles of KHP Initial buret reading (mL) Final buret reading (mL) Volume NaOH solution used (ml) Moles of NaOH used Molarity NaOH Average Molarity of NaOH 0.00171md 0.00170 ud 0.0017 md

  • Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol....

    Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...

  • 1. Calculate the Molarity, NaOH(mol/L) for Standar 1, Standar 2 and Standard 3 with calculations 2....

    1. Calculate the Molarity, NaOH(mol/L) for Standar 1, Standar 2 and Standard 3 with calculations 2. Write and balance the chemical reaction between NaOh and H2SO4 Molarity of standard H2SO4 solution (from the lab container) - 0.2411 M Write and balance the chemical reaction between NaOH and H2S04 (don't forget physical states): Standard 1 Standard 2 Standard 3 NaOH used (mL) (final – initial burette readings] 27.26m H2SO4 (mL) dispensed 15. Om 29.3lmu 16.0mL 31.14 ml 17.0ML Molarity, NaOH (mol/L)...

  • Please help calculate, Concentration of NaOH is 0.1M. Trial 2 Trial 3 Trial 1 C. #502...

    Please help calculate, Concentration of NaOH is 0.1M. Trial 2 Trial 3 Trial 1 C. #502 0.8236g 0.8389g Mass of impure KHP unknown taken (g 0.8167g 0.00mL. 0.00mL 0.00ml. Initial burette reading (mL) 27.52 mL Final burette reading (mL) 27.52 mL 27.87mL 26,72mL Volume of NaOH used (mLO by mass of impure KHP unknown relative average deviation Trial 1 Trial 2 Trial 3 D. #11 0.3602g 0.3636g Mass of unknown acid (g) 0.00ml 0.00mL 10.00mL Initial burette reading (mL) 5.88mL...

  • Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol....

    Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...

  • can you help with the balance equation and also the calculations at the bottom of the...

    can you help with the balance equation and also the calculations at the bottom of the sheet thank you Experiment 17 Acid Base Reactions and Titration Report Sheet Name Section Number Provide the balanced equation for standardizing NaOH below. Table L. Standardization of NaOH Trial Trial 2 Trial 3 Initial mass of flask (g) 85.85 92.9285.80 Mass of flask with KHP (g) Initial buret reading of NaOH (mL) 11.87 19.21 4.21 Initial-buret-reading of NaOH (mL) Final buret reading of NaOH...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT