Question

A population of bacteria doubles every 5 hours. If the initial size of the population is 1 (measured in millions). (a) Find t

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Answer #1

Given,

Doubling rate =5 hours

Initial Population=1(in million)

a)The equation for the population is:

P(t)=1*2^{\frac{t}5}​​​​​​

b)Population after 15 hours =P(15)=1*2^{\frac{15}5}=2^3=8(in million).

c)10=1*2^{\frac{t}5}

log 10={\frac{t}5}=\frac{t}{5}log2=\frac{0.301t}{5}=1

t=\frac{5}{0.301}\simeq16.61

The population will reach 10(in million) after 16.61 hours .

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