4). (3 P oints).The amount of tea leav es in a can from a particular production...
he amount of tea leaves in a can from a particular production line is normally distributed with μ = 110 grams and σ = 25 grams. Approximately 83% of the can will have at least how many grams of tea leaves? Round your answer to 1 decimal place.
The amount of chocolates in a box from a particular production line is normally distributed with μ = 110 grams and σ = 25 grams. A sample of 25 boxes is to be selected. What is the probability that the sample mean will be greater than 100 grams?
The of pyridoxine (in grams) in a multiple vitamin is normally amount distributed with mean 110 grams and standard deviation 25 grams. What is the probability that a randomly selected vitamin will contain between 100 and 120 grams of pyridoxine? 01. 0.0000 02. 0.1244 03. 0.2255 04. 0.3108 05. 0.5682
Statistic Q1(a) Mr. Sweetheart likes sugar in his hot tea. He buys sugar packets from a local grocery store. Suppose the amount of sugar in a packet follows a normal distribution with mean 2.17 grams and standard deviation 0.08 grams. The amount of sugar in a package should be between 2.13 and 2.21 grams. Otherwise, a packet is considered to be defective. i. What is the probability that a randomly selected packet is defective? ii. Three sugar packets are chosen...
Problem 4-24B Allocating joint product cost Mountain Tea Co. makes two products: a high-grade tea branded Wulong and a low-grade tea branded San Tea for the Asian market. Mountain purchases tea leaves from tea firms in mountainous villages of Taiwan and processes the tea leaves into a high-quality product. The tea leaves are dried and baked in the manufacturing process. Mountain pays farmers $600 for 900 kilograms of tea leaves. For 900 kilograms of green leaves, the company can produce...
The patient recovery time for a particular surgical procedure is normally distributed with a a mean of μ = 5.7 days and a standard deviation of σ = 1.2 days. (Round your answers to 3 decimal places.) a) 95% of patients have a recovery time between and . b) What is the recovery time for a patient who is 1.5 standard deviations below the mean? c) If X is the recovery time, compute P(3≤X≤4) and interpret what it means in the context...
Question 2 (4 marks) Part a) A sample of n-25 observations is drawn from a normal population with μ-100 and o-20. Find the following. i) P(X<96) ii) P(96-X-105) Part b) The amount of time the university professors devote to their jobs per week is normally distributed with a mean of 52 hours and a standard deviation of 6 hours. i) What is the probability that a professor works for more than 60 hours per weeks? ii) Find the probability that...
Suppose that 4 tables in a production run of 50 are defective. A sample of 7 is to be selected to be checked for defects 9. How many different samples can be chosen? a. How many samples will contain at least one defective table? b. What is the probability that a randomly chosen sample of 7 contains at least one defective table? c.
Suppose that 4 tables in a production run of 50 are defective. A sample of 7 is...
Question 8 1 pts An inspection on 160 parts made from two production lines at a factory yields the following table. A part is randomly selected from these 160 parts. Line 1 Line 2 total Good 65 82 147 Defective 5 8 13 total 70 90 160 The probability that this part is made from Line 1 is about O 0.41 0.56 O 0.44 0.39 0.03 Question 10 1 pts The following two-way contingency table gives the breakdown of the...
An orange juice producer buys all his oranges from a large orange orchard. The amount of juice squeezed from the oranges is approximately normally distributed with a mean of 4.70 ounces and a standard deviationof 0.40 ounces a.(10) What is the probability that a randomly selected orange will contain i. Between 4.70 and 5.00 ounces? ii. Between 5.00 and 5.50 ounces? ii. Between 4.00 and 5.00 ounces iv. More than 4.00 ounces b. (5) Seventy-seven percent of the oranges will...