Question

- 2 a which feature in the graph in Figure 1.6.4 represents: the distance fallen after the object was released? ii the acceleration of the object? b Describe how the acceleration of the object changed after it was released.

Answer 1

Solution in the uploaded image

Q w R T P S Lock А S D F G к Enter Z C V B Shit En Solutions Terminal speed speed of time goraph of a Time starts exerting Zero NIMI < 1 > 11 21 Speed The graph shown is the jumper. When a jumper jumps it will fall under gravity. After opening Due to gravity its velocity increasing. After it opens para chuite then upward drop face on a parachute which will counter balance the weight of a jumper. At that point, the net force on jumper become Chence accelaration is zero. Therefore jumper will fall with a=0 & u = constant. This constant velocity is called terminal speed, from the above -graphs 02.(a) (i) Distance fallen is given by area under the carve. (ii) Accelariation of the object at point * slope of tangent at particular Time (t). we can see the acceleration decreases with time at terminal point, acceleration become zero. # Hit like if you understood the solutions! is given by the Kangent any (ط) وی and finally