An known mass of liquid water at 25.0 °C is mixed with 65.0 g of water...
An known mass of liquid water at 25.0 °C is mixed with 65.0 g of water at 95.0 °C. The final temperature of the combined water is 49.6 °C. What was the mass of the cooler sample of water? What equation is used for this question.
Homework Answers
After mixing the cooler sample of water will warm up (heat energy "flows" into it)
The warmer water will cool down (heat energy "flows" out of it).
The whole mixture will became at the same temperature.
Energy flow out = Energy flow in
qlost=qgain=m xdelta t xcp
65g x (95-49.6) x4.184 = m x( 49.6-25 ) x4.184
65 x 45.4 / 24.6 =m
m= 119.9 g
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