I need step by step calculation!
R = 250 kΩ
V = 3.0 V
Rmin = 250*0.95 = 237.5 kΩ
Rmax = 250*1.05 = 262.5 kΩ
So Imax = V/Rmin = 3/237.5 = 12.6 uA
and Imin = V/Rmax = 3/262.5 = 11.4 uA
SOLUTION :
R = 250 kΩ
Variation possible I resistance value = 5% I.e. - 5% to + 5% .
Hence,
R minimum = 250 * (1 - 0.05) = 237.5 kΩ
R maximum = 250* (1 + 0.05) = 262.5 kΩ
Voltage applied = 2 * 1,50 = 3.00 V
So,
Minimum current = 3.00 / (262.5 *10^3) = 11.43 * 10^(-6) Amp = 11.43 µA (ANSWER).
Maximum current = 3.00 / (237.5 *10^3) = 12.633 * 10^(-6) Amp = 12.63 µA (ANSWER).
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