use the internet to find the number of seconds since the last epoch (the current epoch is midnight, January 1st, 1970) for your current time. convert the seconds value to days (there are 86400 seconds per day).
how would the resulting decimal value be stored in memory? show each step of your calculations.
Number of seconds since last epoch right now is : 1548965993
1548965993 seconds have been passed since jan 1st , 1970.
seconds = 1548965993
To convert seconds into days we need to divide resultant seconds by 86400
Total days = (1548965993) / 86400
Since total seconds which is obtained is of order around 10^10. So int varible will not be sufficient to store.
To store seconds we need to store in the long int varible
long int seconds = 1548965993 ;
To store the number of days which is obtained after division we can simply store it in float varible
float days = (float)seconds / 86400;
use the internet to find the number of seconds since the last epoch (the current epoch...
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