Question

Given the network in Fig. E9.2, find the average power absorbed by each passive circuit element and the total average power supplied by the current source.

Answer 1

Step 1 : First find zeq  which is 1.84 angle 10.61

Step 2 :  V = IZ 

              V= ( 10 angle 30 ) (1.84angle 10.61)

V = 18.4 angle 40.61

Step 3 Ps = 1/2 Vm Im cos ( theta v - theta i) 

 Ps= 1/2 ( 18.4) (10) cos ( 40.61-30) 

Ps= 90.42W 

Im= (18.4 angle 40.61 )/ 3 

Im= 6.13 angle 40 

 P3ohom = 1/2 ( Im)^2  (3)

   = 1/2 (6.13)^2 (3)

   = 56.36W 

Im= ( 18.4 angle 40.61 )

Im=4.6 angle 40.61

 P4ohm = 1/2 (Im)^2 (4)

       = 1/2 (4.13)^2 (4)

P4ohm = 34.11W