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5. The 0.875-in-diameter solid steel shaft shown below is simply supported with bearings at the ends. Loads are applied to ar

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given a dia d= 0.875 in By Resolving forces at B Finally the torque TR = 500x.7 +200x8 TB = 5100 lb-in Moment Mr = 500x3 +*) Left of point B (Just left) Bending stress To = 324 = 32MBL Td 3 3281330.72 TX(0.875)3 = 20233.1 shear stress T = Toneta d

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