Question

Theorems Regarding Right Angle Triangles

Summarize Euclid's approach to proving proposition 1.47 and 1.48.

1.47: In right-angled triangles, the square on the side subtending the right angle is equal to the squares on the sides containing the right angle.

1.48: If In a triangle the square on one of the sides be equal to the squares on the remaining two sides of the triangle, the angle contained by the remaining two sides of the triangle is right.


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Answer #1
  • PROOF OF PROPOSITION 1.47:

  • THEOREM : 6.7 :

If a perpendicular is drawn from the vertex of the right angle of a right triangle to the hypotenuse then right triangle on bGiven: AABC right angled at B & perpendicular from B intersecting AC at D. (i.e. BD 1 AC) B To Prove: AADB - M ΔABC ΔBDC » ΔA

If a right triangle, the square of the hypotenuse is equal to the sum of the squares of other two sides. B Given: AABC right Using Theorem 6.7: If a perpendicular is drawn from the vertex of the right angle of the a right triangle to the hypotenuse tA ADB ~ A ABC Δ BDC «Δ ABC A Since, sides of similar triangles Since, sides of similar triangles are in the same ratio are in

Hence in this way we can prove Pythagoras Theorem as : AB2 + BC2 = AC.


  • PROOF OF PROPOSITION 1.48:



prop1.pngprop2.pngprop3.png


answered by: Dev Kapadia
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