Question

A test is made of Ho: u= 50 versus H1: u50. A sample of size n = 71 is drawn, and =56. The population standard deviation is o = 29. Compute the value of the test statistic z and determine if H is rejected at the a = 0.05 level. A) 0.21, Ho not rejected B) 1.74, Ho rejected D) 1.74, Ho not rejected C) 0.21, Ho rejected The Golden Comet is a hybrid chicken that is prized for its high egg production rate and gentle disposition. According to recent studies, the mean rate of egg production for 1-year-old Golden Comets is 5.6 eggs/week. Sarah has 47 1-year-old hens that are fed exclusively seeds, and plants that the hens obtain as exhibit on natural scratch feed: insects they range freely around the farm. Her hens egg-laying rate of 6.1 eggs/day. a mean Sarah wants to determine whether the mean laying rate u for her hens is higher than the m rate for all Golden Comets. State the appropriate null and alternate hypotheses. Η: μ < 6.1, Η :μ = 6.1. ΟΗ: μ > 5.6, Η : μ = 5.6 Β) Hoμ= 6.1, Η:μ # 6.1 D) Hg: μ= 5.6, Η : μ > 5.6 A)

Answer 1

Question 1

Based on the information provided, the significance level is a 0.05, and the critical value for a two- tailed test is ze = 1.96 The rejection region for this two-tailed test is R {z : |z| > 1.96} Test Statistics The z-statistic is computed as follows: 56 50 1.743 29//71 Decision about the null hypothesis Since it is observed that z 1.743 < ze = 1.96, it is then concluded that the null hypothesis is not rejected Using the P-value approach: The p-value is p 0.0813, and since p 0.0813 0.05, it is concluded that the null hypothesis is not rejected.

Correct option : D) 1.74, H₀ not rejected

Question 2

Correct option : D) H₀ : $\mu$ = 5.6 , H₁ : $\mu$ > 5.6