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17.7 Disk A, of weight 10 lb and radius r = 6 in., is at rest when it is placed in contact with belt BC, which moves to the r
Fig. P17.7
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086/ Given that Weight = loth radius = 6 in = 0.544 constant Speed N= 40 4415 U = 0.20 - from figure externat acting friction. A = X 8 . = Umq.xrxe KU we have F= UK my In this disk Kinetic energy acting on Since ang ulou Nelocity is constant when T IДхаххө = 1 - р - 1 * 2 x 1 x 1 x 1 Чи ху 0 = N2 4 м 2 rad. - change 0 rad to ren 2.XXX4 Шк 9 Волк 2 Ну от Queso q Омер Hion =answer is ready......

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