Question

A projectile is launched straight up in the air. Its height (in feet) t seconds after launch is given by the function () - 16
0 0
Add a comment Improve this question Transcribed image text
Answer #1

2 St 767E +2791- = Hit = - df at -32t + 329 = velocity ra After 8 bob velocity = 33 (9.9) + 329 = 814 loes 2.30 os Answer.

Add a comment
Know the answer?
Add Answer to:
A projectile is launched straight up in the air. Its height (in feet) t seconds after...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A projectile is fired in the air from a height of 125 feet. Its velocity (in...

    A projectile is fired in the air from a height of 125 feet. Its velocity (in feet per second)t seconds after launch is f(t), given in the following table. X f(x) 0 231 5 205 10 194 15 170 20 152 25 125 30 101 a) How fast is the projectile traveling 15 seconds after launch? | feet per second. b) How far does the projectile move between 5 seconds and 25 seconds? Estimate feet. c) How far does the...

  • A projectile is launched straight up from ground level with an initial velocity of v0 per...

    A projectile is launched straight up from ground level with an initial velocity of v0 per sec. Neglecting air resistance, its height in feet, s, after t seconds after launch is given by the equation s = –16t2 + v0t. At what time(s) will the projectile reach a height of 112 feet when v0 = 96 feet/sec? After how many seconds will it return to the ground when v0 = 96 feet/sec?

  • An arrow is shot into the air and its height in feet after I seconds is...

    An arrow is shot into the air and its height in feet after I seconds is given by the function f(t) = -16° + 128r. Estimate the instantaneous velocity at I = 5 seconds using difference quotients with h = 0.1, 0.01 and 0.001. If necessary, round the difference quotients to no less than six decimal places and round your final answer to the nearest integer 3x - 2 F(x) = 2 – 9x

  • A projectile is launched from ground level with an initial velocity of v 0 feet per...

    A projectile is launched from ground level with an initial velocity of v 0 feet per second. Neglecting air? resistance, its height in feet t seconds after launch is given by s equals negative 16 t squared plus v 0 t. Find the? time(s) that the projectile will? (a) reach a height of 80 ft and? (b) return to the ground when v 0 is 32 feet per second. ?(a) Find the? time(s) that the projectile will reach a height...

  • If a ball is thrown straight up into the air with an initial velocity of 95 ft/s, it height in feet after t second is given by y=95t–16t2

    If a ball is thrown straight up into the air with an initial velocity of 95 ft/s, it height in feet after t second is given by y=95t–16t2. Find the average velocity for the time period begining when t=1 and lasting(i) 01 seconds: (ii) 001 seconds:(iii) 0001 seconds:Finally based on the above results, guess what the instantaneous velocity of the ball is when t=1.

  • 6-An arrow is shot straight up into the air. Its height h (in feet) at any...

    6-An arrow is shot straight up into the air. Its height h (in feet) at any time can be determined by the function h(t) = 128 – 16t. (6 pts.) a) What is the maximum height attained by the arrow? b) How many seconds does the arrow take to reach a height of 192 feet? eps

  • A projectile is launched straight up at 50 m/s from a height of 87 m, at...

    A projectile is launched straight up at 50 m/s from a height of 87 m, at the edge of a sheer cliff. The projectile falls, just missing the cliff and hitting the ground below. (a) Find the maximum height of the projectile above the point of firing. (b) Find the time it takes to hit the ground at the base of the cliff. s (c) Find its velocity at impact. m/s

  • a ball is shot straight up into the air and its height above the ground (in...

    a ball is shot straight up into the air and its height above the ground (in feet) after t seconds is modeled by the functions s(t)=-16t+127t+8. determines the instantaneous velocity of the ball two seconds before it hit the ground 9(x) = -1x – 2+4.

  • A projectile is launched straight up at 57 m/s from a height of 84.5 m, at...

    A projectile is launched straight up at 57 m/s from a height of 84.5 m, at the edge of a sheer cliff. The projectile falls, just missing the cliff and hitting the ground below. (a) Find the maximum height of the projectile above the point of firing. m (b) Find the time it takes to hit the ground at the base of the cliff. s (c) Find its velocity at impact. m/s

  • A projectile is launched straight up at 58.5 m/s from a height of 90 m, at...

    A projectile is launched straight up at 58.5 m/s from a height of 90 m, at the edge of a sheer cliff. The projectile falls, just missing the cliff and hitting the ground below. (a) Find the maximum height of the projectile above the point of firing. m (b) Find the time it takes to hit the ground at the base of the cliff. s (c) Find its velocity at impact. m/s

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
Active Questions
ADVERTISEMENT