Question

Exercise 9.84 - Enhanced - with Feedback 51 of 79 > Review Constanta Pere Table Pertae (CH) is a component of gasoline that burns According to the following balanced equation: C +809) SCO (9) + 6H0 g) Part A You may want to reference Page 392-300) Section 9.10 while completing this problem -146.8 Calculate All for this reaction using Mandard enthalpies of formation. The standard enthalpy of formation of liquid pertas J/mol Express the enthalpy in kilojoules to four sigricant Agures. AWC. Submit

Answer 1

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C5H12 (1) + 802 5 CO2 (g) + 6H20 (9) The standard enthalpy change for this dreaction is calculated by using the formula Dharan = Emolf (product) - En DH / dreactant) Where DHyo (product) = Stand and enthalpy of product DHE (reactant) = Standard enthalpy of reactant m= total mode of product na total male of reactant DH & (CO2) = - 39 3:5 kJ/ml , DHO (120) = - 241.8 kJ/mol DH/ (02) = 0.0 kJ/mol DH f tCg H, 2(1)) = -146.850 / m 2 showm- [5 x (on(com)) + 6 x (D4; (440)] - [10 H, (cstid)t $x[0+( = 5*(-393 . 5 kJ (mod) + 6+ (-241.8 kJ/mal) - (1-146.8 kJ /mal) + 8x10 oksmall = - 1967.5 kJ/mol - 1450.8 kJ/mol + 146.8 kJ/mol =3418.3 + 146-8) kJ/mal = -3271.5 kJ/mol bo DHoon - 3271.5 kJ/mol

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