2) Given y'=4e^2x/y and y(0)=1
We know that y'=dy/fx
Therefore dy/dx=4e^2x/y
ydy=4e^2xdx
Integrating on both sides , we get
y^2/2 = 2e^2x + c
y^2 = 4e^2x +2c
given y(0)=1 means at x=0 y=1
1=4+2c.
Therefore c=-3/2
So y^2=4e^2x-3/2
2. Solve the initial value problem and write y explicitly as a function of a. 4e2...
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