Question

Synchronous communication satellites are placed in a circular orbit that is 1.25 x 10 m above the surface of the earth. What is the magnitude of the acceleration due to gravity at this distance? Number the tolerance +/-29 Click if you would like to Show Work for this questions Open Show Work

Answer 1

Mass of earth

M = 5.972 * 1024 kg

Gravitational constant

G = 6.67 * 10-11 mkg-1,-

Radius of earth

R= 6.37 * 100 m

Distance of satellite above the surface of earth

r = 1.25 * 100 m

Net force acting on the satellite at distance
(R+r)
from the center of earth is
GMm F = (R1T) (R+ r) 2 = mg

Magnitude of acceleration due to gravity at that place is

GM (R+r) 6.67 * 10-11 *5.972 * 1024 = 6.86 m/s (6.37 * 106 + 1.25 * 106)2