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Solve for the mesh currents. I and I in phasor domain, shown in the figure below 50 -110 HA D 6/15 102_90
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Answer #1

5-2 Using Mesh Analysis in I,- -4o + 5I, + jis (I,-I,)=. 15+ji5) I, - JIS I; = 40 l+3;) I, - 3jI2=8 Using Mesh Analysi] in MeOn Solviny equation ☺ &☺ -3+j) I, +. 3I2=8} 9 I,-3I, = 16+3 )I, = 6+ 85 I,= 6+8j II T-189 +1-135j gn phasor I, =1.643243.667

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