Question

An irregularly shaped flat object of mass 2.20 kg is suspended from a point at a distance d from its center of mass and allowed to undergo simple harmonic motion in the vertical plane. The object has moment of inertia I = 1.35 kg · m² about an axis passing through the point of suspension and perpendicular to the plane of the object. The frequency of this oscillatory motion is 0.610 Hz. What is the distance d of the pivot point from the center of mass of the object?

Answer 1

This is like a Phy sical Sy stem Pendulun uhosre Tome Pesied Îs given ky TeM Isupport mg Leine. mg LaM Pivot Paur 1.35 2.2 x918 x LCM Core -0.61HZ O06I Hz = 1-64see 1.35= -> 1.64 = 21.56 Leoi4 =) (1.c4)? = 1.35 21.58 Lainy =) LeM = 1.35 21152 X(l+64)= = 0.023 m= 2.3 cm. Ang k-LaM