Question

li m2[T2 – T3] – m1[T3 – T1] = 0 Q2 01 Experiment 1 Watch the experiment 1 video and extract measurements of T1, T2,T3 and m = mı + m2. Find the mass of each quantity of water without using CAL = 4184J/kg°C. value Please show your working below m = 0.1540 kg m2 (55.6 – 18] – m1 [18 – 3.4] = 0 m2 = (0.38829)m Ti = 3.4 °C given mı + m2 = 0.154kg, mı + m2(0.38829) = 0.154 m = 0.1109kg T2 = 55.6 °C :: m2 =(0.38829)(0.1109) = 0.0431kg T3 = 18.0 °C mı = 0.1109kg. kg m2 = 0.0431kg From your knowledge of heat transfer justify why your equation 1 can still be used: kg

Can someone please explain the last point as I don't quite understand? Thanks!

Answer 1

we know Kormula of Heat tramsfel Q = mS(AT) ms (Tf - Ti) Sy specific Heat calorimety principle Here m mass we know from A TA B TB --- MA M Epi=o MASA (T-TA+MBSB (T-TB) = 0 T final tempo of mixture SA SB -) SA=SB-S IF mixing materials are same sf matt-TA) + MB (T-TB)] -0 MA (T-TA) + MB (T-TB) =)