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write a function in jupyter notebook in python that calculate the # exact derivative value of...

write a function in jupyter notebook in python that

calculate the

# exact derivative value of f(x) = sin^3(x) at x = 1/5

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Answer #1
>>> from sympy import sin
>>> from sympy.abc import x
>>> x =1/5
>>> sin(x).pow(3).diff(x)
>>> 3.x.pow(2).cos(x).pow(3).
>>> 3/25cos(1/5).pow(3)
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