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(1 point) Use the applet provided to draw a phase portrait for = -2x(1 - 2)(2-2) The above equation could represent a model
(1 point) Determine the bifurcation value(s) for the one parameter family k = 0 help (numbers) Determine which differential e
0 0
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Answer #1

x=-22 (1-2) (2-2) Now for x<0, -x20, 1-x>0 and 2-x>0 80 x>0 thus & increases For Oca<1 . -220, 1-ayo and 2-x70 x20 thusou le = y²the dt Now, critical points are given by dy = y² +6=0 Thus for kyo, no critical point for k=0, y=0 is critical poin

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