Solution:
1)
Given:
We have to find P(100<X<146) = ...?
Using z-score,
Therefore,
P(−1.1258 ≤ Z ≤ 0) = P(Z≤0) − P(Z≤−1.1258)
=0.5−0.1301=0.3699 ...Using standard normal table
Hence, P(100<X<146) = 0.3699
2)
Given:
We have to find P(X
36) = ..?
Using z-score,
Therefore,
P(Z≤−2.25)=0.0122
Hence, P(X
36) = 1.22%
Done
If x has a normal distribution with mean=146 and standard deviation = 40.86 , find P...
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