Question

If x has a normal distribution with mean=146 and standard deviation = 40.86 , find P (100 < x < 146) * 2 points Your answer T
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Answer #1

Solution:

1)

Given:

\mu=146

\sigma=40.86

We have to find P(100<X<146) = ...?

Using z-score,

X1 - 21 100 - 146 40.86 = -1.1258 0 X₂ - H 22 146 – 146 40.86 = 0

Therefore,

P(−1.1258 ≤ Z ≤ 0) = P(Z≤0) − P(Z≤−1.1258)

=0.5−0.1301=0.3699 ...Using standard normal table

Hence, P(100<X<146) = 0.3699

2)

Given:

\mu=54

\sigma=8

We have to find P(X\leq 36) = ..?

Using z-score,

X-H Z= 36 - 54 8 = -2.25 o

Therefore,

P(Z≤−2.25)=0.0122

Hence, P(X\leq 36) = 1.22%

Done

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