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Use thermodynamic data to calculate the K_p for the reaction below at 298 K and 1300.0...
Calculate the value of K_p for the reaction 2N_2(g) + O_2(g) reversible 2N_2 O(g) at 298.15...
Calculate the value of K_p for the reaction 2N_2(g) + O_2(g) reversible 2N_2 O(g) at 298.15 K and 1173 K. Thermodynamic data for N_2 O(g) are: delta H degree_t = 82.05 kJ/mol; S degree = 219.9 J/mol middot K; delta G degree f = 104.2 kJ/mol. 298.15 K Did you consider the stoichiometry of the balanced equation for the reaction? Did you check your signs and units? Would you expect K_p at 1173 K to be greater than or less...
For the reaction, the value of K_p is 41.0 (at 400.0 K). and deltaH^n = -92.2...
For the reaction, the value of K_p is 41.0 (at 400.0 K). and deltaH^n = -92.2 kJ N_2(g) + 3 H_2(g) rightarrow 2 NH_3(g) What is the value of K_p at 705.0 K? Collect and Organize Given the values of deltaH_n and K_p for the conversion of N_2 and H_2 to give NH_3 at one temperature, we will calculate the value of K_p at a higher temperature. Analyze What is the expression for the relationship between equilibrium constants at two...
Based on the thermodynamic data below at 298 K, estimate the temperature, in CELSIUS, above which...
Based on the thermodynamic data below at 298 K, estimate the temperature, in CELSIUS, above which the following reaction would be non-spontaneous. FeO(s s) +Fe(s) +02(g)> Fe20,(s) ДН/ (kJ/mol) So (J/K-mol) FeO(s) -271.9 60.75 Fe(s) Fe203 (a) 618.1°C 27.15 205.0 89.96 0 -822.16 (b) 756.3°C (c) 1235°O (d) 2439°C (e) spontaneous at all temperatures
Based on the thermodynamic data below at 298 K, estimate the temperature, in CELSIUS, above which the following reaction would be non-spontaneous. FeO(s s) +Fe(s) +02(g)>...
At 850. K, the value of the equilibrium constant K_p for the hydrazine synthesis reaction below...
At 850. K, the value of the equilibrium constant K_p for the hydrazine synthesis reaction below is 0.1900. N_2(g) + H_2(g) rightwardsharpoonoverleftwardsharpoon N_2H_2(g) If a vessel contains an initial reaction mixture in which [N_2] = 0.01000 M, [H_2] = 0.02500 M, and [N_2H_2] = 1.000 times 10^-4 M, what will the [N_2H_2] be when equilibrium is reached? M
Use the data below, for 298.15 K, to calculate the thermodynamic equilibrium constant, kp, at 641...
Use the data below, for 298.15 K, to calculate the thermodynamic equilibrium constant, kp, at 641 K for the following reaction. NH4Cl(s) NH3(g) + HCl(g) ΔΗ /kJ mol-1 -314.4 -45.9 -92.3 Smº /JK-mol-1 94.6 192.8 186.9 Cp.m /JK-mol-1 84.1 35.1 29.1 Do not use the Van't Hoff equation, In(K/K) = -(AHR/R) (T2-1-T1-1) The value of the thermodynamic equilibrium constant is Kp = Number
Use the data below, for 298.15 K, to calculate the thermodynamic equilibrium constant, kp, at 839...
Use the data below, for 298.15 K, to calculate the thermodynamic equilibrium constant, kp, at 839 K for the following reaction. NH4Cl(s) NH3(g) + HCl(g) ΔΗ 7 kJ mol-1 -314.4 -45.9 -92.3 Smº JK-1 mol-1 94.6 192.8 186.9 Cp,m 84.1 35.1 29.1 /JK-1 mol-1 Do not use the Van't Hoff equation, In(K /K1) = -(AHR/R) (T2-1 - 7,-1) The value of the thermodynamic equilibrium constant is Kp= 7.6e14
Use the provided thermodynamic data at 298 K and partial pressures given to decide in which...
Use the provided thermodynamic data at 298 K and partial pressures given to decide in which direction (forward or backward) the reaction will proceed under these conditions: Compound ΔG (kJ/mol) Partial Pressure (atm) SO2 (g) -300.2 1.0 x 10-4 O2 (g) 0.0 0.20 SO3 (g) -371.1 0.10
Given the thermodynamic data below, calculate the value of the equilibrium constant for the reaction shown...
Given the thermodynamic data below, calculate the value of the
equilibrium constant for the reaction shown at 25.0ºC
H₂ (g) + I₂ (g) ⇄ 2 HI (g)
Given the thermodynamic data below, calculate the value of the equilibrium constant for the reaction shown at 25.0°C H2(g) + 12 (g) = 2 HI(g) AH° = -9.48 kJ AS° = +21.79 J/K K= at 25.0°C Check
Consider the reaction given below. H2(g) + F2(g) 2 HF(g) (a) Using thermodynamic data from the...
Consider the reaction given below.
H2(g) + F2(g)
2 HF(g)
(a) Using thermodynamic data from the course website, calculate
G° at 298 K.
kJ
(b) Calculate G at 298 K if the reaction mixture
consists of 5.1 atm of H2, 4.8 atm of F2, and
0.19 atm of HF.
kJ
Consider the reaction given below. H2(g) + F2(g) 2 HF(g) (a) Using thermodynamic data from the...
Consider the reaction given below.
H2(g) + F2(g)
2 HF(g)
(a) Using thermodynamic data from the course website, calculate
G° at 298 K.
____ kJ
(b) Calculate G at 298 K if the reaction mixture
consists of 8.3 atm of H2, 3.0 atm of F2, and
0.26 atm of HF.
____ kJ
Calculate the value of K_p for the reaction 2N_2(g) + O_2(g) reversible 2N_2 O(g) at 298.15 K and 1173 K. Thermodynamic data for N_2 O(g) are: delta H degree_t = 82.05 kJ/mol; S degree = 219.9 J/mol middot K; delta G degree f = 104.2 kJ/mol. 298.15 K Did you consider the stoichiometry of the balanced equation for the reaction? Did you check your signs and units? Would you expect K_p at 1173 K to be greater than or less...
For the reaction, the value of K_p is 41.0 (at 400.0 K). and deltaH^n = -92.2 kJ N_2(g) + 3 H_2(g) rightarrow 2 NH_3(g) What is the value of K_p at 705.0 K? Collect and Organize Given the values of deltaH_n and K_p for the conversion of N_2 and H_2 to give NH_3 at one temperature, we will calculate the value of K_p at a higher temperature. Analyze What is the expression for the relationship between equilibrium constants at two...
Based on the thermodynamic data below at 298 K, estimate the temperature, in CELSIUS, above which the following reaction would be non-spontaneous. FeO(s s) +Fe(s) +02(g)> Fe20,(s) ДН/ (kJ/mol) So (J/K-mol) FeO(s) -271.9 60.75 Fe(s) Fe203 (a) 618.1°C 27.15 205.0 89.96 0 -822.16 (b) 756.3°C (c) 1235°O (d) 2439°C (e) spontaneous at all temperatures
Based on the thermodynamic data below at 298 K, estimate the temperature, in CELSIUS, above which the following reaction would be non-spontaneous. FeO(s s) +Fe(s) +02(g)>...
At 850. K, the value of the equilibrium constant K_p for the hydrazine synthesis reaction below is 0.1900. N_2(g) + H_2(g) rightwardsharpoonoverleftwardsharpoon N_2H_2(g) If a vessel contains an initial reaction mixture in which [N_2] = 0.01000 M, [H_2] = 0.02500 M, and [N_2H_2] = 1.000 times 10^-4 M, what will the [N_2H_2] be when equilibrium is reached? M
Use the data below, for 298.15 K, to calculate the thermodynamic equilibrium constant, kp, at 641 K for the following reaction. NH4Cl(s) NH3(g) + HCl(g) ΔΗ /kJ mol-1 -314.4 -45.9 -92.3 Smº /JK-mol-1 94.6 192.8 186.9 Cp.m /JK-mol-1 84.1 35.1 29.1 Do not use the Van't Hoff equation, In(K/K) = -(AHR/R) (T2-1-T1-1) The value of the thermodynamic equilibrium constant is Kp = Number
Use the data below, for 298.15 K, to calculate the thermodynamic equilibrium constant, kp, at 839 K for the following reaction. NH4Cl(s) NH3(g) + HCl(g) ΔΗ 7 kJ mol-1 -314.4 -45.9 -92.3 Smº JK-1 mol-1 94.6 192.8 186.9 Cp,m 84.1 35.1 29.1 /JK-1 mol-1 Do not use the Van't Hoff equation, In(K /K1) = -(AHR/R) (T2-1 - 7,-1) The value of the thermodynamic equilibrium constant is Kp= 7.6e14
Given the thermodynamic data below, calculate the value of the
equilibrium constant for the reaction shown at 25.0ºC
H₂ (g) + I₂ (g) ⇄ 2 HI (g)
Given the thermodynamic data below, calculate the value of the equilibrium constant for the reaction shown at 25.0°C H2(g) + 12 (g) = 2 HI(g) AH° = -9.48 kJ AS° = +21.79 J/K K= at 25.0°C Check
Consider the reaction given below.
H2(g) + F2(g)
2 HF(g)
(a) Using thermodynamic data from the course website, calculate
G° at 298 K.
kJ
(b) Calculate G at 298 K if the reaction mixture
consists of 5.1 atm of H2, 4.8 atm of F2, and
0.19 atm of HF.
kJ
Consider the reaction given below.
H2(g) + F2(g)
2 HF(g)
(a) Using thermodynamic data from the course website, calculate
G° at 298 K.
____ kJ
(b) Calculate G at 298 K if the reaction mixture
consists of 8.3 atm of H2, 3.0 atm of F2, and
0.26 atm of HF.
____ kJ
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