Question

aAn electron is then shot between the plates

Course Contents >> ... >> HW2 > An electron is then shot between the plates Notes Bookmark Evaluate Communicate Print Info V L- In the figure, a uniform, upward-pointing electric field E of magnitude 4.50X10' N/C has been set up between two horizontal plates by charging the lower plate positively and the upper plate negatively. The plates have length L = 4 cm and separation d = 2.00 cm. Electrons are shot between the plates from the left edge of the lower plate. The first electron has the initial velocity vo, which makes an angle =45° with the lower plate and has a magnitude of 8.71x109 m/s. Will this electron strike one of the plates? If so, what is the horizontal distance from the left edge? If not enter the vertical position at which the particle leaves the space between the plates. .008m Submit Answer Incorrect. Tries 8/10 Previous Tries Another electron has an initial velocity which has the angle 8=45° with the lower plate and has a magnitude of 6.09x105 m/s. Will this electron strike one of the plates? If so, what is the horizontal distance from the left edge? If not enter the vertical position at which the particle leaves the space between the plates. 2.39x10^-2m Submit Answer Incorrect. Tries 1/10 Previous Tries This discussion is closed. A Send Feedback

Answer 1

As the electric field is constant, the electrons will undergo projectile motion.

PROJECTILE MOTION celeration constant - R R is the range of the particle (electron) h is the maximum height attained R=u²sin 20 h= u sinto 29. acceleration = 95.88 m u initial velocity o initial Angle with horizontal an Acceleration downwards. a) Net fence on electron, 113 R = 78.71X10) sin(90%) Faqe (25/m) acceleration - 2€ - 0 ITR = qs.sexions h = (8.71x106)? sinļus -) Stimme mat borterton 219€/m) ti uloso t= 4x10²m = 14.59x109) (52) sec. 8071x10x cosuso" =) Vertical distance at t = (usinolt - Lať = 2.36 em . - It will strike the upper plate. Time taken to cover L, Th=93.97x 103 m

> S = ut-at? 2x16? = 8.11x10ʻrcesusxt - L x PEx ť? 3.87x102-6.158 x 10-t +2x102= 0 . t = 4.55 x109 sec. horizontal distance Covered = (uloso) (+) = 2.8 cm For (b) Part, ? R=(6.09X106) singo (28/m) = It will not strike horizontall plate. - = 4.68 cm bottom ha u²sinto = 1.17 cm (max. height) at K. time for R=L. 3) +- Yucato = 9.28 x 10° sec. k - u+--- 4.6 x 1 x 1 x 1 x 1 (6)- [h= 0.59 cm at 11 = 4cm] - 4cm
a) part

distance = 2.8 cm = 0.028 m

b) part

distance = 0.59 cm = 0.0059 m