![Void Message { char sz_all=Well Come To KSU: char* psz_x; uint i = 1; psz x=&sz a[0]; while (psz_x !0) { *psz = *sz +i; i=](http://img.homeworklib.com/questions/a2a1afe0-552f-11ec-b4d5-2de6623354c5.png?x-oss-process=image/resize,w_560)
Homework Answers
2.There is some syntax error in the code if you remove that error like in place of psz it should be psz_x and sz a it should be sz_a.
(1) If you correct them then the method Message is doing left shifting of the character in the character array and storing to psz_x.While loop will be continues till the end of the character array .
First psz_x point to the 0th character of the sz_a
And in while loop it will goes to next character till the last character.
(2)Array will store "elcome to ksu" after the final execution. As psu_x assigning one character next from the array sz_a.
If you have any doubt, please ask me in comment box. Thanks!
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Void Message { char sz_all="Well Come To KSU": char* psz_x; uint i = 1; psz x=&sz...
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