using kVL in right loop
2 R i + R i2 = E3 - 45 * 10^-3
2 * 1.5* 10^6* 40* 10^-9 + 1.5* 10^6* i2 = E3 - 45 * 10^-3
0.12 + 1.5* 10^6 i2 = E3 - 45* 10^-3
0 i1 + 1.5* 10^6 i2 - E3 = - 0.165.. (i)
usting kVL in left loop
2 * 1.5* 10^6* 40* 10^-9 + 2 * 1.5* 10^6* i1 = E3 - 75 * 10^-3
0.12 + 3* 10^6 i1 = E3 - 75* 10^-3
3* 10^6 i1 + 0 i2 - E3 = - 0.195... (ii)
using kCL
i1 + i2 = 40* 10^-9... (iii)
solving(i), (ii) and (iii)
E3 = 215 mV
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What is the value of E3? An electrochemical impulse traveling along the cell modeled in the...
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