Question

3.72 E What are 9.05 E C2 4.12 and charge q3, (b) tential difference Vs, and (c) stored energy Us for capacitor 3, (d) q1, (e) V, and(f) 1 for capacitor 1, and (9) q2, (h) V2, and (j) U2 for capacitor 2? In the figure a potential difference V-130 V is applied across a capacitor arrangement with capacitances C Cs Unit (a) NumbefT484 (b) Numbe130 (c) NumberT3.1e4 (d) Numbe 367.9 (e) NumbefT40.65 (f) Number 117477.6 (g) Numbe367.9 (h) Numbes9.3 UnitsTj Units UnitsTv UnitsT uC UnitsT v

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Answer #1

c) energy stored in C3 = 1/2 C V2

= 0.5 * 3.72 *10-6 * 1302 = 0.0314 J

f) U1 for capacitor 1 = 1/2 C1 V12

= 1/2 * 9.05 * 10-6 * 40.652

= 7.48 * 10-3 J = 0.00748 J

i) U2 for capacitor 2

= 1/2 * 4.12 * 10-6 * 89.32= 0.0164 J

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