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2. Consider the nonlinear BVP y = 2y3 – 6y – 2x, 15152, y(1) = 2, y(2) Use h = 0.1 to approximate the solution using the no
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Answer #1

This question is based on Differential calculus & related non-linear Boundary value problem.

To solve this question you must need to understand these concepts.

1) differentiation equation.

2 ) non-linear Boundary value problem.

3) Non-linear shooting method.

  1. Solution J = 2y-cy-222 15262 , 9 (1) 22 (2) 25 = 293_68-203 Chron d age f (0,95) = 245-64-222 x2 Y=0 y = 0 del 9:12 113 114rЧи = 3; + ( z1), Zitt = zi + fz (21.34s, Zi)h is! X2 121 12 -- yoz Velo A x 21 9 = 2, Zo=4, 2011 Y Z I + f (1, 2, 4) or = 2 tz = 2 4 + f (1:1, 2, 7, 8) oil 73 z = 2.0t Out 28g - Z rf (1.1, 2.0, tors. z & t 2 (2.033 – 682.9 – 2(1.173 - ¢ t 27,640 - 94uc - Yut tilky, Yy, Zy) of a 25a6 + 36 23 =Yqtfi (113, 7:26, 38.23) o.) = 4:26 + 3.82 Ys Rion] 28= 2q + f2 (+3, 226, 38.20052 Y t fi (de + y + Zc/o) = 24.3 C t. 26.3 - 26+ f (1.5 24.36, 263) or -- 203 + 12628-32). CX24:36 = 2(15)*Joy 2 263 + 2075707Yg= yot fi (kor, Yoo, Zo)ol. =yout 2913 = 364.5+2913 = 3277.5 Blizz = 2a+ fal benig, 369.5, 2913).) ay z 29131 * 2913 1 = yg- - o o 2. - 15 | 20g. - 112 ху - 1 3 o o х - 2, 4. 2. 4. 2 с. God. ( 9 2 Ч:32 Socc 3CC.S 327,5 фабче 2 164 14.4 799 = 5 - |
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