Question

tion: (sand)+ BaCla H₂O -> BaCl₂ + 2 H2O + (sand) Data: mass of crucibe. - 26.481g Rid, and mixture Mass of empty 21.0219 crucibe and lid mass of crucible, itd, 26.1639 and sample ofter it neating mass of crucible, ind, and sample after and heating - Calculation: using the data provide above and the balanced equation for barium Clorpae othedrate decompos roten determine the mass and percent of sand in mixtur Show work. mass of sand in the mixture percent of sand in the mixture Following up question: Why is it important to heat the mixture more than once?

Answer 1

Griven, Sand & Backe H20 D Ball +240 + Sanel x mass of cracibe, lid = 26.4819 + Sample (M+Ms) * moss of empth crucibe & did = 21.021 g. mass of (Mama) moss of (Me+Ms) thead = 26.163g - 25-964 g no → M - 26.481 - 21.021 = 5.4609 (Ms het hart = 25-464 – 21.021 = 4.1439 Ms mass of sample (Sand & Heel & Bach

* Dorkially Mixdurite contains, Sand & Backs. H₂O But after heating we lost H₂O of moisture = ? Now, mixture contions Sand & back, dost amount of H ₂ O Ms - (Ms) = 5-460-4.9kB ad Heat 20.517 m According to ea. Imol (Back. He ) will give a mols of H₂O I mot ho = 18 gm = 0.517 m HO = 0.517 18 20.028 ml (2) 0.029 mod to Released beg 0.029 mol (Back, whe) as I mol (Bally. 20) = 2 mals (HO).

. The sample contains 0.029 = 0.0143 mol of Bach, .2H20 (of) Baca, mol of Back = 208 gm 2 0.0143 mol of Bada = 208*0.0143 am - 2-987 am mass of sand .=) = (Ms) na - 2.987 I from ② l = 4.843 - 2-187 = 1.95 m

% "Somla Sand - 1.95 1.95 5.46 = 35.7% Reheaking of mixture - To ensure all of the H₂O is everforstad - And H₂O molecules same times setzels between Voids af sand. - So, it is important to theat.