x | n | p | |
1 | 385 | 1100 | 0.35 |
2 | 341 | 1100 | 0.31 |
Using Excel<data<megastat<hypothesis test<compare two independent proportions
Here is the output:
Hypothesis test for two independent proportions | |||||
p1 | p2 | pc | |||
0.35 | 0.31 | 0.33 | p (as decimal) | ||
385/1100 | 341/1100 | 726/2200 | p (as fraction) | ||
385. | 341. | 726. | X | ||
1100 | 1100 | 2200 | n | ||
0.04 | difference | ||||
0. | hypothesized difference | ||||
0.02 | std. error | ||||
2.00 | z | ||||
.0460 | p-value (two-tailed) | ||||
0.0007 | confidence interval 95.% lower | ||||
0.0793 | confidence interval 95.% upper | ||||
0.0393 | margin of error |
Answers:
a) The proportion of the adults who took the 1942 survey who were total abstainers 0.35 and 0.31.
b) Option A,C,D
Hypothesis
Ho:p1=p2
Ha:p1 not equal p2
Test Statistic = 2.00
P-value= 0.460
If the population proportions are equal one would expect a sample difference proportion greater than the one observed in about 46 out of 100.
Conclusion: Option A
Since p-value > alpha(0.05). We fail to reject the null hypothesis.
Do not reject Ho: There is not sufficient evidence at alpha =0.05 level of significance.
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