Question

3. Calculate the absorbance of a solution given that the transmission is 37.8%. 4. Given that the concentration of the compound giving rise to the absorption (A-0.4520) is 8.62 mmol L1, what is the molar absorption coefficient when measured through a cell of length 0.20 cm?

Please explain in detail so I can understand both of the questions. Thankyou.
Please also take into account the mantissa significant figures which is a requirement for the two questions.

Answer 1

Transmittence II = 37.8%. =0. 375 Beer's law As per Lambert & A = – 10g (IlIo) = Elt A = -log (0.378) = -(-0.4225) A = 0.4225 Atsortance of the 501= 0.4225 Absorption (A)= 0.452o concth of soin con= 8.52 mmol/2 = 8.62X10 3M length (i)= 0. 20 cm. we know that A = Ece E molar absorption coefficient E = Alce = 0.4520/3.62x10-3 x 0.20 0.4520 Mttmt 1.724 x 10-3 6 = 262,181 Mt Chry Ans molar absorption to7 Hicient (E)= 252,161 Mtemi